Question
Answer
$$-2\sqrt{27}+7\sqrt{48}=22\sqrt{3}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}-2\sqrt{27}+7\sqrt{48}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-6\sqrt{3}+28\sqrt{3} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}22\sqrt{3}\end{aligned} $$ | |
| ① | $$ - 2 \sqrt{27} =
-2 \sqrt{ 3 ^2 \cdot 3 } =
-2 \sqrt{ 3 ^2 } \, \sqrt{ 3 } =
-2 \cdot 3 \sqrt{ 3 } =
-6 \sqrt{ 3 } $$ |
| ② | $$ 7 \sqrt{48} =
7 \sqrt{ 4 ^2 \cdot 3 } =
7 \sqrt{ 4 ^2 } \, \sqrt{ 3 } =
7 \cdot 4 \sqrt{ 3 } =
28 \sqrt{ 3 } $$ |
| ③ | Combine like terms |
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