Question
Answer
$$(9+\sqrt{3})\cdot(-8+\sqrt{11})=-72+9\sqrt{11}-8\sqrt{3}+\sqrt{33}$$
Explanation
| $$ \begin{aligned}(9+\sqrt{3})\cdot(-8+\sqrt{11})& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-72+9\sqrt{11}-8\sqrt{3}+\sqrt{33}\end{aligned} $$ | |
| ① | $$ \color{blue}{ \left( 9 + \sqrt{3}\right) } \cdot \left( -8 + \sqrt{11}\right) = \color{blue}{9} \cdot-8+\color{blue}{9} \cdot \sqrt{11}+\color{blue}{ \sqrt{3}} \cdot-8+\color{blue}{ \sqrt{3}} \cdot \sqrt{11} = \\ = -72 + 9 \sqrt{11}- 8 \sqrt{3} + \sqrt{33} $$ |
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