Question
Answer
$$(7+3\sqrt{6})\cdot(-9-7\sqrt{5})=-63-49\sqrt{5}-27\sqrt{6}-21\sqrt{30}$$
Explanation
| $$ \begin{aligned}(7+3\sqrt{6})\cdot(-9-7\sqrt{5})& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-63-49\sqrt{5}-27\sqrt{6}-21\sqrt{30}\end{aligned} $$ | |
| ① | $$ \color{blue}{ \left( 7 + 3 \sqrt{6}\right) } \cdot \left( -9- 7 \sqrt{5}\right) = \color{blue}{7} \cdot-9+\color{blue}{7} \cdot- 7 \sqrt{5}+\color{blue}{ 3 \sqrt{6}} \cdot-9+\color{blue}{ 3 \sqrt{6}} \cdot- 7 \sqrt{5} = \\ = -63- 49 \sqrt{5}- 27 \sqrt{6}- 21 \sqrt{30} $$ |
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