Question
Answer
$$(7+\sqrt{5})\cdot(-9+\sqrt{2})=-63+7\sqrt{2}-9\sqrt{5}+\sqrt{10}$$
Explanation
| $$ \begin{aligned}(7+\sqrt{5})\cdot(-9+\sqrt{2})& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-63+7\sqrt{2}-9\sqrt{5}+\sqrt{10}\end{aligned} $$ | |
| ① | $$ \color{blue}{ \left( 7 + \sqrt{5}\right) } \cdot \left( -9 + \sqrt{2}\right) = \color{blue}{7} \cdot-9+\color{blue}{7} \cdot \sqrt{2}+\color{blue}{ \sqrt{5}} \cdot-9+\color{blue}{ \sqrt{5}} \cdot \sqrt{2} = \\ = -63 + 7 \sqrt{2}- 9 \sqrt{5} + \sqrt{10} $$ |
This page was created using
Simplify Radical Expression