Question
Answer
$$(3+\sqrt{2})\cdot(-7+\sqrt{10})=-21+3\sqrt{10}-7\sqrt{2}+2\sqrt{5}$$
Explanation
| $$ \begin{aligned}(3+\sqrt{2})\cdot(-7+\sqrt{10})& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-21+3\sqrt{10}-7\sqrt{2}+2\sqrt{5}\end{aligned} $$ | |
| ① | $$ \color{blue}{ \left( 3 + \sqrt{2}\right) } \cdot \left( -7 + \sqrt{10}\right) = \color{blue}{3} \cdot-7+\color{blue}{3} \cdot \sqrt{10}+\color{blue}{ \sqrt{2}} \cdot-7+\color{blue}{ \sqrt{2}} \cdot \sqrt{10} = \\ = -21 + 3 \sqrt{10}- 7 \sqrt{2} + 2 \sqrt{5} $$ |
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