Question
Answer
$$(3+2\sqrt{2})\cdot(-4+\sqrt{10})=-12+3\sqrt{10}-8\sqrt{2}+4\sqrt{5}$$
Explanation
| $$ \begin{aligned}(3+2\sqrt{2})\cdot(-4+\sqrt{10})& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-12+3\sqrt{10}-8\sqrt{2}+4\sqrt{5}\end{aligned} $$ | |
| ① | $$ \color{blue}{ \left( 3 + 2 \sqrt{2}\right) } \cdot \left( -4 + \sqrt{10}\right) = \color{blue}{3} \cdot-4+\color{blue}{3} \cdot \sqrt{10}+\color{blue}{ 2 \sqrt{2}} \cdot-4+\color{blue}{ 2 \sqrt{2}} \cdot \sqrt{10} = \\ = -12 + 3 \sqrt{10}- 8 \sqrt{2} + 4 \sqrt{5} $$ |
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