Question
Answer
$$(2\sqrt{6}-7)^2=73-28\sqrt{6}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(2\sqrt{6}-7)^2& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}24-14\sqrt{6}-14\sqrt{6}+49 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}73-28\sqrt{6}\end{aligned} $$ | |
| ① | $$ (2\sqrt{6}-7)^2 = \left( 2 \sqrt{6}-7 \right) \cdot \left( 2 \sqrt{6}-7 \right) = 24- 14 \sqrt{6}- 14 \sqrt{6} + 49 $$ |
| ② | Combine like terms |
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