| $$ \begin{aligned}(-9\sqrt{2})\cdot4\sqrt{6}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-72\sqrt{3}\end{aligned} $$ | |
| ① | $$ - 36 \sqrt{12} =
-36 \sqrt{ 2 ^2 \cdot 3 } =
-36 \sqrt{ 2 ^2 } \, \sqrt{ 3 } =
-36 \cdot 2 \sqrt{ 3 } =
-72 \sqrt{ 3 } $$ |