Question
Answer
$$-6-\sqrt{7}\cdot(-6+\sqrt{5})=-6+6\sqrt{7}-\sqrt{35}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}-6-\sqrt{7}\cdot(-6+\sqrt{5})& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-6-(-6\sqrt{7}+\sqrt{35}) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-6+6\sqrt{7}-\sqrt{35}\end{aligned} $$ | |
| ① | $$ \color{blue}{ \sqrt{7} } \cdot \left( -6 + \sqrt{5}\right) = \color{blue}{ \sqrt{7}} \cdot-6+\color{blue}{ \sqrt{7}} \cdot \sqrt{5} = \\ = - 6 \sqrt{7} + \sqrt{35} $$ |
| ② | Remove the parentheses by changing the sign of each term within them. $$ -\left( - 6 \sqrt{7} + \sqrt{35} \right) = 6 \sqrt{7}- \sqrt{35} $$ |
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