$$ \begin{aligned} y+3 &= \frac{1}{4}y+5&& \text{multiply ALL terms by } \color{blue}{ 4 }. \\[1 em]4y+4\cdot3 &= 4 \cdot \frac{1}{4}y+4\cdot5&& \text{cancel out the denominators} \\[1 em]4y+12 &= y+20&& \text{move the $ \color{blue}{ y } $ to the left side and $ \color{blue}{ 12 }$ to the right} \\[1 em]4y-y &= 20-12&& \text{simplify left and right hand side} \\[1 em]3y &= 8&& \text{ divide both sides by $ 3 $ } \\[1 em]y &= \frac{8}{3}&& \\[1 em] \end{aligned} $$

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