$$ \begin{aligned} y+15 &= 4y&& \text{move the $ \color{blue}{ 4y } $ to the left side and $ \color{blue}{ 15 }$ to the right} \\[1 em]y-4y &= -15&& \text{simplify left side} \\[1 em]-3y &= -15&& \text{ divide both sides by $ -3 $ } \\[1 em]y &= \frac{-15}{-3}&& \\[1 em]y &= 5&& \\[1 em] \end{aligned} $$
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