Question
$$x\cdot2-4x+x\cdot2-6x+9-x+x-3 = 0$$
Answer
$$ x = 1 $$
Explanation
$$ \begin{aligned} x\cdot2-4x+x\cdot2-6x+9-x+x-3 &= 0&& \text{simplify left side} \\[1 em]x\cdot2-4x+x\cdot2-6x+9-x+x-3 &= 0&& \\[1 em]-6x+6 &= 0&& \text{ move the constants to the right } \\[1 em]-6x &= -6&& \text{ divide both sides by $ -6 $ } \\[1 em]x &= \frac{-6}{-6}&& \\[1 em]x &= 1&& \\[1 em] \end{aligned} $$
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