$$ \begin{aligned} x\cdot2+5x-14(x+7) &= 0&& \text{simplify left side} \\[1 em]7x-14(x+7) &= 0&& \\[1 em]7x-(14x+98) &= 0&& \\[1 em]7x-14x-98 &= 0&& \\[1 em]-7x-98 &= 0&& \text{ move the constants to the right } \\[1 em]-7x &= 98&& \text{ divide both sides by $ -7 $ } \\[1 em]x &= -\frac{98}{7}&& \\[1 em]x &= -14&& \\[1 em] \end{aligned} $$

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