Question
$$x\cdot6-2x\cdot5+x\cdot4+x\cdot3-x-8 = 0$$
Answer
$$ x = 4 $$
Explanation
$$ \begin{aligned} x\cdot6-2x\cdot5+x\cdot4+x\cdot3-x-8 &= 0&& \text{simplify left side} \\[1 em]6x-10x+4x+3x-x-8 &= 0&& \\[1 em]2x-8 &= 0&& \text{ move the constants to the right } \\[1 em]2x &= 8&& \text{ divide both sides by $ 2 $ } \\[1 em]x &= \frac{8}{2}&& \\[1 em]x &= 4&& \\[1 em] \end{aligned} $$
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