Question
$$x^5-2x^4-16x+32 = x^5-2x^4-16x+32$$
Answer
The equation has an infinite number of solutions.
Explanation
$$ \begin{aligned} x^5-2x^4-16x+32 &= x^5-2x^4-16x+32&& \text{move all terms to the left hand side } \\[1 em]x^5-2x^4-16x+32-x^5+2x^4+16x-32 &= 0&& \text{simplify left side} \\[1 em]x^5-2x^4-16x+32-x^5+2x^4+16x-32 &= 0&& \\[1 em]0 &= 0&& \\[1 em] \end{aligned} $$
Since the statement $ \color{blue}{ 0 = 0 } $ is TRUE for any value of $ x $, we conclude that the equation has infinitely many solutions.
This page was created using
Equations Solver