$$ \begin{aligned} \frac{x}{5}+4 &= \frac{x}{3}&& \text{multiply ALL terms by } \color{blue}{ 15 }. \\[1 em]15 \cdot \frac{x}{5}+15\cdot4 &= 15 \cdot \frac{x}{3}&& \text{cancel out the denominators} \\[1 em]3x+60 &= 5x&& \text{move the $ \color{blue}{ 5x } $ to the left side and $ \color{blue}{ 60 }$ to the right} \\[1 em]3x-5x &= -60&& \text{simplify left side} \\[1 em]-2x &= -60&& \text{ divide both sides by $ -2 $ } \\[1 em]x &= \frac{-60}{-2}&& \\[1 em]x &= 30&& \\[1 em] \end{aligned} $$
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