$$ \begin{aligned} x(x+2) &= x(x-3)+2&& \text{simplify left and right hand side} \\[1 em]x^2+2x &= x^2-3x+2&& \text{move all terms to the left hand side } \\[1 em]x^2+2x-x^2+3x-2 &= 0&& \text{simplify left side} \\[1 em]x^2+2x-x^2+3x-2 &= 0&& \\[1 em]5x-2 &= 0&& \text{ move the constants to the right } \\[1 em]5x &= 2&& \text{ divide both sides by $ 5 $ } \\[1 em]x &= \frac{2}{5}&& \\[1 em] \end{aligned} $$

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