Question
$$x\cdot(6-x) = 36$$
Answer
$$ \begin{matrix}x_1 = 3+3 \sqrt{ 3 }i & x_2 = 3-3 \sqrt{ 3 }i \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} x\cdot(6-x) &= 36&& \text{simplify left side} \\[1 em]6x-x^2 &= 36&& \\[1 em]-x^2+6x &= 36&& \text{move all terms to the left hand side } \\[1 em]-x^2+6x-36 &= 0&& \\[1 em] \end{aligned} $$
$ -x^{2}+6x-36 = 0 $ is a quadratic equation.
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