Question
$$a^2+4a+2-3a-6 = 29$$
Answer
$$ \begin{matrix}a_1 = -\dfrac{ 1 }{ 2 }-\dfrac{\sqrt{ 133 }}{ 2 } & a_2 = -\dfrac{ 1 }{ 2 }+\dfrac{\sqrt{ 133 }}{ 2 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} a^2+4a+2-3a-6 &= 29&& \text{simplify left side} \\[1 em]a^2+a-4 &= 29&& \text{move all terms to the left hand side } \\[1 em]a^2+a-4-29 &= 0&& \text{simplify left side} \\[1 em]a^2+a-33 &= 0&& \\[1 em] \end{aligned} $$
$ x^{2}+x-33 = 0 $ is a quadratic equation.
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