$$ \begin{aligned} 9-7 \cdot \frac{n}{3} &= 5 \cdot \frac{n}{2}&& \text{multiply ALL terms by } \color{blue}{ 6 }. \\[1 em]6\cdot9-6\cdot7 \cdot \frac{n}{3} &= 6\cdot5 \cdot \frac{n}{2}&& \text{cancel out the denominators} \\[1 em]54-14n &= 15n&& \text{move the $ \color{blue}{ 15n } $ to the left side and $ \color{blue}{ 54 }$ to the right} \\[1 em]-14n-15n &= -54&& \text{simplify left side} \\[1 em]-29n &= -54&& \text{ divide both sides by $ -29 $ } \\[1 em]n &= \frac{-54}{-29}&& \\[1 em]n &= \frac{54}{29}&& \\[1 em] \end{aligned} $$

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