Question
$$9(x+3)-4x\cdot77 = 0$$
Answer
$$ x = \dfrac{27}{299} $$
Explanation
$$ \begin{aligned} 9(x+3)-4x\cdot77 &= 0&& \text{simplify left side} \\[1 em]9(x+3)-308x &= 0&& \\[1 em]9x+27-308x &= 0&& \\[1 em]-299x+27 &= 0&& \text{ move the constants to the right } \\[1 em]-299x &= -27&& \text{ divide both sides by $ -299 $ } \\[1 em]x &= \frac{-27}{-299}&& \\[1 em]x &= \frac{27}{299}&& \\[1 em] \end{aligned} $$
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