Question
$$8x\cdot3-36x+27 = 0$$
Answer
$$ x = \dfrac{9}{4} $$
Explanation
$$ \begin{aligned} 8x\cdot3-36x+27 &= 0&& \text{simplify left side} \\[1 em]24x-36x+27 &= 0&& \\[1 em]-12x+27 &= 0&& \text{ move the constants to the right } \\[1 em]-12x &= -27&& \text{ divide both sides by $ -12 $ } \\[1 em]x &= \frac{-27}{-12}&& \\[1 em]x &= \frac{9}{4}&& \\[1 em] \end{aligned} $$
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