Question
$$8x-9(3x-1)(x+3) = 0$$
Answer
$$ \begin{matrix}x_1 = -\dfrac{ 32 }{ 27 }-\dfrac{\sqrt{ 1753 }}{ 27 } & x_2 = -\dfrac{ 32 }{ 27 }+\dfrac{\sqrt{ 1753 }}{ 27 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 8x-9(3x-1)(x+3) &= 0&& \text{simplify left side} \\[1 em]8x-(27x-9)(x+3) &= 0&& \\[1 em]8x-(27x^2+81x-9x-27) &= 0&& \\[1 em]8x-(27x^2+72x-27) &= 0&& \\[1 em]8x-27x^2-72x+27 &= 0&& \\[1 em]-27x^2-64x+27 &= 0&& \\[1 em] \end{aligned} $$
$ -27x^{2}-64x+27 = 0 $ is a quadratic equation.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this equation.
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