$$ \begin{aligned} 8c-4(c+3) &= 8&& \text{simplify left side} \\[1 em]8c-(4c+12) &= 8&& \\[1 em]8c-4c-12 &= 8&& \\[1 em]4c-12 &= 8&& \text{ move -12 to the right } \\[1 em]4c &= 8+12&& \\[1 em]4c &= 20&& \text{ divide both sides by $ 4 $ } \\[1 em]c &= \frac{20}{4}&& \\[1 em]c &= 5&& \\[1 em] \end{aligned} $$
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