$$ \begin{aligned} \frac{81}{9}3x\cdot3 &= 0&& \text{multiply ALL terms by } \color{blue}{ 9 }. \\[1 em]9 \cdot \frac{81}{9}3x\cdot3 &= 9\cdot0&& \text{cancel out the denominators} \\[1 em]729x &= 0&& \text{ divide both sides by $ 729 $ } \\[1 em]x &= \frac{0}{729}&& \\[1 em]x &= 0&& \\[1 em] \end{aligned} $$
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