$$ \begin{aligned} 8-\frac{3}{8}x-4 &= 0&& \text{multiply ALL terms by } \color{blue}{ 8 }. \\[1 em]8\cdot8-8 \cdot \frac{3}{8}x-8\cdot4 &= 8\cdot0&& \text{cancel out the denominators} \\[1 em]64-3x-32 &= 0&& \text{simplify left side} \\[1 em]-3x+32 &= 0&& \text{ move the constants to the right } \\[1 em]-3x &= -32&& \text{ divide both sides by $ -3 $ } \\[1 em]x &= \frac{-32}{-3}&& \\[1 em]x &= \frac{32}{3}&& \\[1 em] \end{aligned} $$
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