$$ \begin{aligned} 8-2 \cdot \frac{x}{x}+3 &= 0&& \text{multiply ALL terms by } \color{blue}{ x }. \\[1 em]x\cdot8-x\cdot2 \cdot \frac{x}{x}+x\cdot3 &= x\cdot0&& \text{cancel out the denominators} \\[1 em]8x-2x+3x &= 0&& \text{simplify left side} \\[1 em]9x &= 0&& \text{ divide both sides by $ 9 $ } \\[1 em]x &= \frac{0}{9}&& \\[1 em]x &= 0&& \\[1 em] \end{aligned} $$

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