$$ \begin{aligned} 8-2(x+4) &= 2x&& \text{simplify left side} \\[1 em]8-(2x+8) &= 2x&& \\[1 em]8-2x-8 &= 2x&& \\[1 em]8-2x-8 &= 2x&& \\[1 em]-2x &= 2x&& \text{move the $ \color{blue}{ 2x } $ to the left side} \\[1 em]-2x-2x &= 0&& \text{simplify left side} \\[1 em]-4x &= 0&& \text{ divide both sides by $ -4 $ } \\[1 em]x &= \frac{0}{-4}&& \\[1 em]x &= 0&& \\[1 em] \end{aligned} $$

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