$$ \begin{aligned} \frac{8}{3}x-4 &= \frac{2}{3}x-\frac{5}{3}&& \text{multiply ALL terms by } \color{blue}{ 3 }. \\[1 em]3 \cdot \frac{8}{3}x-3\cdot4 &= 3 \cdot \frac{2}{3}x-3\cdot\frac{5}{3}&& \text{cancel out the denominators} \\[1 em]8x-12 &= 2x-5&& \text{move the $ \color{blue}{ 2x } $ to the left side and $ \color{blue}{ -12 }$ to the right} \\[1 em]8x-2x &= -5+12&& \text{simplify left and right hand side} \\[1 em]6x &= 7&& \text{ divide both sides by $ 6 $ } \\[1 em]x &= \frac{7}{6}&& \\[1 em] \end{aligned} $$

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