$$ \begin{aligned} 8(2x+5) &= 7(x+3)+11&& \text{simplify left and right hand side} \\[1 em]16x+40 &= 7x+21+11&& \\[1 em]16x+40 &= 7x+32&& \text{move the $ \color{blue}{ 7x } $ to the left side and $ \color{blue}{ 40 }$ to the right} \\[1 em]16x-7x &= 32-40&& \text{simplify left and right hand side} \\[1 em]9x &= -8&& \text{ divide both sides by $ 9 $ } \\[1 em]x &= -\frac{8}{9}&& \\[1 em] \end{aligned} $$

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