$$ \begin{aligned} 7y &= 6+3(y+2)&& \text{simplify right side} \\[1 em]7y &= 6+3y+6&& \\[1 em]7y &= 3y+12&& \text{move the $ \color{blue}{ 3y } $ to the left side} \\[1 em]7y-3y &= 12&& \text{simplify left side} \\[1 em]4y &= 12&& \text{ divide both sides by $ 4 $ } \\[1 em]y &= \frac{12}{4}&& \\[1 em]y &= 3&& \\[1 em] \end{aligned} $$
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