Question
$$7x(5x-4) = 14$$
Answer
$$ \begin{matrix}x_1 = \dfrac{ 2 }{ 5 }-\dfrac{\sqrt{ 14 }}{ 5 } & x_2 = \dfrac{ 2 }{ 5 }+\dfrac{\sqrt{ 14 }}{ 5 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 7x(5x-4) &= 14&& \text{simplify left side} \\[1 em]35x^2-28x &= 14&& \text{move all terms to the left hand side } \\[1 em]35x^2-28x-14 &= 0&& \\[1 em] \end{aligned} $$
$ 35x^{2}-28x-14 = 0 $ is a quadratic equation.
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