$$ \begin{aligned} 7(n+3) &= 7\cdot2+7\cdot3&& \text{simplify left and right hand side} \\[1 em]7n+21 &= 14+21&& \\[1 em]7n+21 &= 35&& \text{ move 21 to the right } \\[1 em]7n &= 35-21&& \\[1 em]7n &= 14&& \text{ divide both sides by $ 7 $ } \\[1 em]n &= \frac{14}{7}&& \\[1 em]n &= 2&& \\[1 em] \end{aligned} $$
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