Question
$$7 = (x+3)^2-9$$
Answer
$$ \begin{matrix}x_1 = 1 & x_2 = -7 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 7 &= (x+3)^2-9&& \text{simplify right side} \\[1 em]7 &= x^2+6x+9-9&& \\[1 em]7 &= x^2+6x+9-9&& \\[1 em]7 &= x^2+6x&& \text{move all terms to the left hand side } \\[1 em]7-x^2-6x &= 0&& \text{simplify left side} \\[1 em]-x^2-6x+7 &= 0&& \\[1 em] \end{aligned} $$
$ -x^{2}-6x+7 = 0 $ is a quadratic equation.
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