Question
$$\frac{7}{3}x-\frac{4}{x} = 1\cdot0$$
Answer
$$ \begin{matrix}x_1 = -2 \dfrac{\sqrt{ 21 }}{ 7 } & x_2 = \dfrac{ 2 \sqrt{ 21}}{ 7 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} \frac{7}{3}x-\frac{4}{x} &= 1\cdot0&& \text{multiply ALL terms by } \color{blue}{ 3x }. \\[1 em]3x \cdot \frac{7}{3}x-3x\cdot\frac{4}{x} &= 3x\cdot1\cdot0&& \text{cancel out the denominators} \\[1 em]7x^2-12 &= 0&& \\[1 em] \end{aligned} $$
$ 7x^{2}-12 = 0 $ is a quadratic equation.
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