Question
$$7\cdot3+15-7\cdot(10-6) = 0$$
Answer
This equation has no solution.
Explanation
$$ \begin{aligned} 7\cdot3+15-7\cdot(10-6) &= 0&& \text{simplify left side} \\[1 em]21+15-7\cdot4 &= 0&& \\[1 em]21+15-28 &= 0&& \\[1 em]8 &= 0&& \\[1 em] \end{aligned} $$
Since the statement $ \color{red}{ 8 = 0 } $ is FALSE, we conclude that the equation has no solution.
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