$$ \begin{aligned} 7(y+3) &= 5y+8&& \text{simplify left side} \\[1 em]7y+21 &= 5y+8&& \text{move the $ \color{blue}{ 5y } $ to the left side and $ \color{blue}{ 21 }$ to the right} \\[1 em]7y-5y &= 8-21&& \text{simplify left and right hand side} \\[1 em]2y &= -13&& \text{ divide both sides by $ 2 $ } \\[1 em]y &= -\frac{13}{2}&& \\[1 em] \end{aligned} $$

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