Question
$$7\cdot2^2-5\cdot2+6 = 0$$
Answer
This equation has no solution.
Explanation
$$ \begin{aligned} 7\cdot2^2-5\cdot2+6 &= 0&& \text{simplify left side} \\[1 em]7\cdot2^2-10+6 &= 0&& \\[1 em]7\cdot4-10+6 &= 0&& \\[1 em]28-10+6 &= 0&& \\[1 em]24 &= 0&& \\[1 em] \end{aligned} $$
Since the statement $ \color{red}{ 24 = 0 } $ is FALSE, we conclude that the equation has no solution.
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