$$ \begin{aligned} 6x-3 \cdot \frac{x^2}{3}x &= 0&& \text{multiply ALL terms by } \color{blue}{ 3 }. \\[1 em]3\cdot6x-33 \cdot \frac{x^2}{3}x &= 3\cdot0&& \text{cancel out the denominators} \\[1 em]18x-3x &= 0&& \text{simplify left side} \\[1 em]15x &= 0&& \text{ divide both sides by $ 15 $ } \\[1 em]x &= \frac{0}{15}&& \\[1 em]x &= 0&& \\[1 em] \end{aligned} $$

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