Question
$$6x-10(x-1)\cdot2(x+14) = 0$$
Answer
$$ \begin{matrix}x_1 = -\dfrac{ 127 }{ 20 }-\dfrac{\sqrt{ 21729 }}{ 20 } & x_2 = -\dfrac{ 127 }{ 20 }+\dfrac{\sqrt{ 21729 }}{ 20 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 6x-10(x-1)\cdot2(x+14) &= 0&& \text{simplify left side} \\[1 em]6x-(10x-10)\cdot2(x+14) &= 0&& \\[1 em]6x-(20x-20)(x+14) &= 0&& \\[1 em]6x-(20x^2+280x-20x-280) &= 0&& \\[1 em]6x-(20x^2+260x-280) &= 0&& \\[1 em]6x-20x^2-260x+280 &= 0&& \\[1 em]-20x^2-254x+280 &= 0&& \\[1 em] \end{aligned} $$
$ -20x^{2}-254x+280 = 0 $ is a quadratic equation.
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