Question
$$6-(3x+1)+2(4x-3) = 0$$
Answer
$$ x = \dfrac{1}{5} $$
Explanation
$$ \begin{aligned} 6-(3x+1)+2(4x-3) &= 0&& \text{simplify left side} \\[1 em]6-(3x+1)+8x-6 &= 0&& \\[1 em]6-3x-1+8x-6 &= 0&& \\[1 em]-3x+5+8x-6 &= 0&& \\[1 em]5x-1 &= 0&& \text{ move the constants to the right } \\[1 em]5x &= 1&& \text{ divide both sides by $ 5 $ } \\[1 em]x &= \frac{1}{5}&& \\[1 em] \end{aligned} $$
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