Question
$$6(4z+1)\cdot6 = 0$$
Answer
$$ z = -\dfrac{1}{4} $$
Explanation
$$ \begin{aligned} 6(4z+1)\cdot6 &= 0&& \text{simplify left side} \\[1 em](24z+6)\cdot6 &= 0&& \\[1 em]144z+36 &= 0&& \text{ move the constants to the right } \\[1 em]144z &= -36&& \text{ divide both sides by $ 144 $ } \\[1 em]z &= -\frac{36}{144}&& \\[1 em]z &= -\frac{1}{4}&& \\[1 em] \end{aligned} $$
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