$$ \begin{aligned} 6(4y-2(y-1))-2+7y &= 0&& \text{simplify left side} \\[1 em]6(4y-(2y-2))-2+7y &= 0&& \\[1 em]6(4y-2y+2)-2+7y &= 0&& \\[1 em]6(2y+2)-2+7y &= 0&& \\[1 em]12y+12-2+7y &= 0&& \\[1 em]19y+10 &= 0&& \text{ move the constants to the right } \\[1 em]19y &= -10&& \text{ divide both sides by $ 19 $ } \\[1 em]y &= -\frac{10}{19}&& \\[1 em] \end{aligned} $$

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