$$ \begin{aligned} 5y+3 &= -7y+13&& \text{move the $ \color{blue}{ -7y } $ to the left side and $ \color{blue}{ 3 }$ to the right} \\[1 em]5y+7y &= 13-3&& \text{simplify left and right hand side} \\[1 em]12y &= 10&& \text{ divide both sides by $ 12 $ } \\[1 em]y &= \frac{10}{12}&& \\[1 em]y &= \frac{5}{6}&& \\[1 em] \end{aligned} $$
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