$$ \begin{aligned} 5x\cdot2-13 &= 7+3x\cdot2&& \text{move the $ \color{blue}{ 6x } $ to the left side and $ \color{blue}{ -13 }$ to the right} \\[1 em]10x-6x &= 7+13&& \text{simplify left and right hand side} \\[1 em]4x &= 20&& \text{ divide both sides by $ 4 $ } \\[1 em]x &= \frac{20}{4}&& \\[1 em]x &= 5&& \\[1 em] \end{aligned} $$
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