Question
$$5+\frac{20}{4}\cdot3-2 = 0$$
Answer
This equation has no solution.
Explanation
$$ \begin{aligned} 5+\frac{20}{4}\cdot3-2 &= 0&& \text{multiply ALL terms by } \color{blue}{ 4 }. \\[1 em]4\cdot5+4 \cdot \frac{20}{4}\cdot3-4\cdot2 &= 4\cdot0&& \text{cancel out the denominators} \\[1 em]20+60-8 &= 0&& \text{simplify left side} \\[1 em]72 &= 0&& \\[1 em] \end{aligned} $$
Since the statement $ \color{red}{ 72 = 0 } $ is FALSE, we conclude that the equation has no solution.
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