$$ \begin{aligned} 5+\frac{(2-3)^2}{1}x\cdot2 &= 0&& \text{multiply ALL terms by } \color{blue}{ 1 }. \\[1 em]1\cdot5+1 \cdot \frac{(2-3)^2}{1}x\cdot2 &= 1\cdot0&& \text{cancel out the denominators} \\[1 em]5+2x &= 0&& \text{ move the constants to the right } \\[1 em]2x &= -5&& \text{ divide both sides by $ 2 $ } \\[1 em]x &= -\frac{5}{2}&& \\[1 em] \end{aligned} $$

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