$$ \begin{aligned} 5c+\frac{161}{2} &= \frac{131}{2}+10c&& \text{multiply ALL terms by } \color{blue}{ 2 }. \\[1 em]2\cdot5c+2\cdot\frac{161}{2} &= 2\cdot\frac{131}{2}+2\cdot10c&& \text{cancel out the denominators} \\[1 em]10c+161 &= 131+20c&& \text{move the $ \color{blue}{ 20c } $ to the left side and $ \color{blue}{ 161 }$ to the right} \\[1 em]10c-20c &= 131-161&& \text{simplify left and right hand side} \\[1 em]-10c &= -30&& \text{ divide both sides by $ -10 $ } \\[1 em]c &= \frac{-30}{-10}&& \\[1 em]c &= 3&& \\[1 em] \end{aligned} $$

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