Question
$$500+50+10+2x\cdot10-2x\cdot1 = 0$$
Answer
$$ x = -\dfrac{280}{9} $$
Explanation
$$ \begin{aligned} 500+50+10+2x\cdot10-2x\cdot1 &= 0&& \text{simplify left side} \\[1 em]500+50+10+20x-2x &= 0&& \\[1 em]18x+560 &= 0&& \text{ move the constants to the right } \\[1 em]18x &= -560&& \text{ divide both sides by $ 18 $ } \\[1 em]x &= -\frac{560}{18}&& \\[1 em]x &= -\frac{280}{9}&& \\[1 em] \end{aligned} $$
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