Question
$$5-8x\cdot2x+3 = 0$$
Answer
$$ \begin{matrix}x_1 = - \dfrac{\sqrt{ 2 }}{ 2 } & x_2 = \dfrac{\sqrt{ 2 }}{ 2 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 5-8x\cdot2x+3 &= 0&& \text{simplify left side} \\[1 em]5-16x^2+3 &= 0&& \\[1 em]-16x^2+8 &= 0&& \\[1 em] \end{aligned} $$
$ -16x^{2}+8 = 0 $ is a quadratic equation.
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